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13x+14=x^2
We move all terms to the left:
13x+14-(x^2)=0
determiningTheFunctionDomain -x^2+13x+14=0
We add all the numbers together, and all the variables
-1x^2+13x+14=0
a = -1; b = 13; c = +14;
Δ = b2-4ac
Δ = 132-4·(-1)·14
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*-1}=\frac{-28}{-2} =+14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*-1}=\frac{2}{-2} =-1 $
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